| 标题 | 发布时间 | 回答数 | 提问者 |
|---|---|---|---|
| 数字 [数列] | 2022-01-23 | 1 | JD1***393 |
| 数字 [数列] | 2022-01-23 | 1 | JD1***393 |
| 数字 [数列] | 2022-01-23 | 1 | JD1***393 |
| 已知等比数列[an]满足a2a5=2a [数列] | 2022-01-23 | 1 | bbm*** |
| 己知等差数列[an]>0，前n项和Sn [数列] | 2022-01-23 | 1 | bbm*** |
| 已知正项等差数列[an]前n项和为Sn [数列] | 2022-01-23 | 1 | bbm*** |
| 数学 [数列] | 2022-01-23 | 1 | JD1***767 |
| 数列 [数列] | 2022-01-23 | 3 | w* |
| 老师那这是不是也算是一种通项公式 [数列] | 2022-01-23 | 3 | JD1***465 |
| 老师是为什么这里老师说S2是这个数列的 [数列] | 2022-01-22 | 1 | JD1***465 |
| 老师答案得几分、 [数列] | 2022-01-22 | 3 | afu*** |
| 老师这步是怎么变得？ [数列] | 2022-01-22 | 3 | JD1***285 |
| 帮忙求解 蟹蟹 [数列] | 2022-01-22 | 5 | DXM*** |
| 14题 [数列] | 2022-01-22 | 4 | cpy***529 |
| 13题 [数列] | 2022-01-22 | 3 | cpy***529 |
| 12题 [数列] | 2022-01-22 | 1 | cpy***529 |
| 老师，什么是正项等比数列 [数列] | 2022-01-22 | 1 | cpy***529 |
| 用an+1与an相减得出4n-3再把7 [数列] | 2022-01-22 | 1 | JD1***091 |
| 为什么是n－1项 [数列] | 2022-01-22 | 1 | JD1***051 |
| 这是如何到第二步的 [数列] | 2022-01-22 | 1 | VIP***406 |
