| 标题 | 发布时间 | 回答数 | 提问者 |
|---|---|---|---|
| 2020-08-06 | 1 | nan***z12 | |
| 2020-08-06 | 3 | src*** | |
| 老师为什么要这样说呢? [数与式] | 2020-08-06 | 2 | z18***292 |
| 2020-08-05 | 1 | JD1***011 | |
| 2020-08-05 | 1 | JD1***011 | |
| 2020-08-05 | 1 | JD1***011 | |
| 不改变值,去-号,系数化整,如图 [数与式] | 2020-08-05 | 1 | fjh*** |
| 不改变值,化去-号,系数为整 如图 [数与式] | 2020-08-05 | 1 | fjh*** |
| 已知实数abcd,a≠b,c≠d,a² [数与式] | 2020-08-05 | 2 | fjh*** |
| (x+1)(x+6)(x+3)(x+4 [数与式] | 2020-08-05 | 1 | fjh*** |
| (x²+4x+8)²+3x(x²+4x [数与式] | 2020-08-05 | 1 | fjh*** |
| x6次方+14x³y+49y²,因式分 [方程(组)与不等式(组)] | 2020-08-05 | 1 | fjh*** |
| x²+xy=12,xy+y²,求(x+ [不确定] | 2020-08-05 | 1 | fjh*** |
| 见下图 [不确定] | 2020-08-05 | 1 | fjh*** |
| 2020-08-05 | 1 | rwd***817 | |
| (x²-x)²+(x²-x)-6因式分 [数与式] | 2020-08-05 | 1 | fjh*** |
| x四次方+80x²-81因式分解 [数与式] | 2020-08-05 | 1 | fjh*** |
| ab+a+b+1因式分解 [不确定] | 2020-08-05 | 1 | fjh*** |
| 已知a+a分之1=3,求a²+a²分之 [数与式] | 2020-08-05 | 1 | fjh*** |
| 2020-08-05 | 1 | qia***e35 |

