| 标题 | 解决时间 | 回答数 | 回答者 |
|---|---|---|---|
| 等比数列中,满足图,求通项公式;Sn为 [不确定] | 2021-01-23 | 2 | |
| 已知q>1的等比数列满足图,求,通项公 [不确定] | 2021-01-23 | 2 | |
| 等差数列的公差d<0,且满足图,则通项 [数列] | 2021-01-23 | 2 | |
| 将数列{2n-1}和{3n-2}的公共 [数列] | 2021-01-23 | 2 | |
| 设数列{an}的前n项和为Sn,满足图 [数列] | 2021-01-23 | 2 | |
| 已知等差数列,求当n为何值时,数列{a [数列] | 2021-01-23 | 2 | |
| 2021-01-23 | 1 | ||
| 2021-01-23 | 1 | ||
| 2021-01-23 | 1 | ||
| 2021-01-23 | 1 | ||
| 2021-01-23 | 1 | ||
| 2021-01-23 | 1 | ||
| 2021-01-23 | 5 | ||
| 怎麼來的 [导数] | 2021-01-23 | 3 | |
| 这个函数的切线不可以是这样的吗,为啥是 [函数] | 2021-01-23 | 1 | |
| 2021-01-23 | 1 | ||
| 2021-01-23 | 3 | ||
| 我觉得这样简单好多 [数列] | 2021-01-23 | 1 | |
| 2021-01-23 | 2 | ||
| 老师,请问到底什么是导数呢,我不是很理 [不确定] | 2021-01-23 | 1 |

